Two numbers, with a difference of 10, have a sum of 34. What is the algebraic equation for this?

I know the answers are 22 and 12, but I'm trying to figure out the equation for a 4th grader to figure it out. I haven't done this in years...Two numbers, with a difference of 10, have a sum of 34. What is the algebraic equation for this?
Let the first one : X


Let the second one : Y





X + Y = 34


X - Y = 10Two numbers, with a difference of 10, have a sum of 34. What is the algebraic equation for this?
You have two equations with two unknowns:





a - b = 10, solve for a = (10 + b)





a + b = 34, substitute (10 + b) + b = 34 =%26gt; 2b + 10 = 34 =%26gt; 2b = 34-10 = 24, so b = 12





since a = b + 10, a = 12+10 = 22
x + y = 34


x - y = 10
a-b=10


a+b=34


Add together: 2a=44, so a=22 substitute to get b=10
Let the mumber be x and x+10


So x+ (x+10)=34


2x+10=34


2x=24


x=12


Numbers are 12 and 22

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