How to design and write a C program logic to find all the numbers that are multiples of 7?

the multiples of 7 need to be in a range of numbers starging at input-value-1 and going to input-value-2. Input-value-2 must be great than input-value-1. I need to place all the multiples of 7 in a 1-dimensional array and keep a count.How to design and write a C program logic to find all the numbers that are multiples of 7?
The main logic for your program is:





declare integer array x[];


input lower bound, upper bound;





for( i = lower bound to upper bound )


if i (mod 7) = 0; (i.e 0 modulus mean multiple of that number)


then x[counter]=i (i.e that number)


print x[0 to max];


print count = max;





now i write this program in c , i write it in turboC compiler, to use it copy this code and paste it in turboC compiler.





//********** Code Starts From Here*****************





#include%26lt;conio.h%26gt;


#include%26lt;stdio.h%26gt;





void main(void)


{


int input_value1, input_value2, i;


int counter=0, result[50];





printf(';Enter Lower Bound:';);


scanf(';%d';,%26amp;input_value1);


printf(';Enter Upper Bound:';);


scanf(';%d';,%26amp;input_value2);





for(i=input_value1;i%26lt;input_value2;i++)


{


if(i%7==0)


{


result[counter++]=i;


}


}


printf(';The multiples of 7 in between the range %d to %d is:';,input_value1,input_value2);


for(i=0;i%26lt;counter;i++)


{


printf(';%3d,';,result[i]);


}


printf(';\n\nThe number of multiple is :%d';,counter);





getche();


clrscr();


}


//*****Code Ends Here******How to design and write a C program logic to find all the numbers that are multiples of 7?
try this:





int low, high;


// Somehow fill low, high with input


int i, n;


int result[(high-low)/7+1];


for (n = 0, i = low; i %26lt;= high; i++) if (i % 7 == 0) result[n++] = i;


// Then print out result[]

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